I hope this is the right area to post this question.

Find the equation of the tangent to the curve y=2/x+1 at the point where x=3.

I had a go can somebody please check it thanks,

y=2/x+1

y=2/4

=1/2 (3,1/2)

2(x+1)^-1

-2(x+1)^-2

-2/(x+1)^2

2/(3+1)(3+1)

2/8

=1/4

therefore in y=mx+b form:

y=1/4x+b

1/2=1/4(3)+b

b=2/3

y=1/4x+2/3

I have done that and I think I have done it correctly but the answer I have is

x+8y-7=0

How can I get this answer or is this wrong.