16^x - 4^(2x-2) + 2^(3x) = 4 I've gotten to: 2^4x - 2^2(2x-2) + 2^3x = 2^2 I've gotten beyond lost after here... I've also tried dividing by 2^2 to get.... 2^(4x-2) - 2^(4x-6) + 2^(3x-2) = 1 but I'm not sure what I can do with this
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Originally Posted by Intrusion 16^x - 4^(2x-2) + 2^(3x) = 4 I've gotten to: 2^4x - 2^2(2x-2) + 2^3x = 2^2 I've gotten beyond lost after here... Very good! You can reduce that a little more Now, let and the equation becomes or but, frankly, I don't see any simple solution to that. I've also tried dividing by 2^2 to get.... 2^(4x-2) - 2^(4x-6) + 2^(3x-2) = 1 but I'm not sure what I can do with this
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