# Math Help - Simplifying- verify if this correct

1. ## Simplifying- verify if this correct

$sin^3(x+1)tan^4x + tan^2xsin^3(x+1)$

$= sin^3(x+1)tan^2x(tan^2x + 1)$

$= sin^3(x+1)tan^2x(1/(cos^2x))$

$= (sin^3(x+1)tan^2x)/(cos^2x)$

2. Originally Posted by shane99
$sin^3(x+1)tan^4x + tan^2xsin^3(x+1)$

$= sin^3(x+1)tan^2x(tan^2x + 1)$

$= sin^3(x+1)tan^2x(1/(cos^2x))$

$= (sin^3(x+1)tan^2x)/(cos^2x)$
I see no problem with that. Remember that $\frac{1}{cos^2 \theta} = sec^2 \theta$