Thread: Work shown: Solve the triangle a=3, c=1, B=100?

a=3, c=1, B=100
b²=3²+1²-2(3*1)cos100
b²=10-4cos100
b=3.27
sin100/3.27=sinA/3
sinA=sin100*3/3.27
A=64.62 degrees
C=15.37 degrees
Now, the problem is this - the back of my book says b=3.32. How is this possible? Help? [:

Originally Posted by Voluntarius Disco

a=3, c=1, B=100
b²=3²+1²-2(3*1)cos100
b²=10-4cos100

This is wrong,

Awesome! Thank you.