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Math Help - Work shown: Solve the triangle a=3, c=1, B=100?

  1. #1
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    Work shown: Solve the triangle a=3, c=1, B=100?



    a=3, c=1, B=100
    bē=3ē+1ē-2(3*1)cos100
    bē=10-4cos100
    b=3.27
    sin100/3.27=sinA/3
    sinA=sin100*3/3.27
    A=64.62 degrees
    C=15.37 degrees
    Now, the problem is this - the back of my book says b=3.32. How is this possible? Help? [:
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  2. #2
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    Quote Originally Posted by Voluntarius Disco View Post

    a=3, c=1, B=100
    bē=3ē+1ē-2(3*1)cos100
    bē=10-4cos100
    This is wrong,

    b^2 = 3^2+1^2-2\times 3\times 1\times \cos 100

    b^2 = 10-6 \cos 100
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  3. #3
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    Awesome! Thank you.
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