Write the equation of a hyperbola satisfying the given condition:
with asymptotes y=-x and y=x+2 and vertical tranverse axis length of 4.
vertical tranverse axis
so hyperbola opens up and down
length of 4
so 2b=4, b=2
intersection of y=-x and y=x+2 is (-1,1)
so centre is (-1,1)
The equation so far is:
(x+1)² / a² - (y-1)² /2² = -1
But what is the value of a? How do you find a?