Remember (definition/properties of abs. val.) that for , so:

,and now you have an "and" inequality system: both the left AND the right inequalities have to be true, so solve them separately and then take the intersection of the separate solutions. For example:

, and since both the numerator and the denominator are ALWAYS positive (why?)

this inequality is true for all ;

...and now can you see why this is ALWAYS negative?

Interestingly enough, the given inequality is true for all x, imo, and thus I can't understand why they gave you that ...

Tonio