I am not understanding this. When I do the arithmetic, it comes out to $\displaystyle \frac{0}{0}$, but thats not right. Any suggestions? Evaluate the limit, if it exists. (If it does not exist, enter NONE).
Follow Math Help Forum on Facebook and Google+
$\displaystyle \frac{t^2-16}{2t^2+9t+4} = \frac{(t-4)(t+4)}{(t+4)(2t+1)}$ now try again..
View Tag Cloud