# Thread: Different equation solve with Bi

1. ## Different equation solve with Bi

Solve the equation and express each solution in the form of A + Bi

2x^2-6X+3=0

2. Originally Posted by victorfk06
Solve the equation and express each solution in the form of A + Bi

2x^2-6X+3=0
Dear victorfk06,

$2x^2-6x+3=0$

$x^2-3x+\frac{3}{2}=0$ (divide the whole equation by 2)

$\left(x-\frac{3}{2}\right)^2-\frac{9}{4}+\frac{3}{2}=0$

$\left(x-\frac{3}{2}\right)^2-\frac{3}{4}=0$

$x-\frac{3}{2}= \pm{\frac{\sqrt{3}}{2}}$

Therefore, $x = \frac{\sqrt{3}+3}{2}$ or $x = \frac{-\sqrt{3}+3}{2}$

This equation has real roots. So it is not necesary to express it in the form A+Bi.

Hope this helps.