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Math Help - Different equation solve with Bi

  1. #1
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    Different equation solve with Bi

    Solve the equation and express each solution in the form of A + Bi

    2x^2-6X+3=0
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  2. #2
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    Quote Originally Posted by victorfk06 View Post
    Solve the equation and express each solution in the form of A + Bi

    2x^2-6X+3=0
    Dear victorfk06,

    2x^2-6x+3=0

    x^2-3x+\frac{3}{2}=0 (divide the whole equation by 2)

    \left(x-\frac{3}{2}\right)^2-\frac{9}{4}+\frac{3}{2}=0

    \left(x-\frac{3}{2}\right)^2-\frac{3}{4}=0

    x-\frac{3}{2}= \pm{\frac{\sqrt{3}}{2}}

    Therefore, x = \frac{\sqrt{3}+3}{2} or x = \frac{-\sqrt{3}+3}{2}

    This equation has real roots. So it is not necesary to express it in the form A+Bi.

    Hope this helps.
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