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Math Help - Functions even, odd, or neither

  1. #1
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    Functions even, odd, or neither

    Can someone answer this problem, and explain it to me. Thank you!

    a) f(x) = e^(-x^2)
    b) f(x) = 1 + sin^-1(-x)
    c) f(x) = abs value e^x
    d) f(x) = e^(ln abs value (x) +1

    Thanks so much!
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  2. #2
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    f(-1)=f(1) Even
    f(-1)=-f(1) Odd
    ex f(x)=X^2 is even
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  3. #3
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    Quote Originally Posted by calculuskid1 View Post
    f(-1)=f(1) Even
    f(-1)=-f(1) Odd
    ex f(x)=X^2 is even

    There should be x not 1 or -1.
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  4. #4
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    Still don't understand that is at all...
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  5. #5
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    Quote Originally Posted by KarlosK View Post
    Still don't understand that is at all...

    if \color{blue}f(-x)=f(x) then \color{blue}f is an even function.
    if \color{blue}f(-x)=-f(x) then \color{blue}f is an odd function.
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  6. #6
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    In other words, use the definition of "even" and "odd" function.

    f(x)= e^{x^2} so f(-x)= e^{(-x)^2} but (-x)^2= x^2 so f(-x)= e^{x^2}= f(x).
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