# Thread: Functions even, odd, or neither

1. ## Functions even, odd, or neither

Can someone answer this problem, and explain it to me. Thank you!

a) f(x) = e^(-x^2)
b) f(x) = 1 + sin^-1(-x)
c) f(x) = abs value e^x
d) f(x) = e^(ln abs value (x) +1

Thanks so much!

2. f(-1)=f(1) Even
f(-1)=-f(1) Odd
ex f(x)=X^2 is even

3. Originally Posted by calculuskid1
f(-1)=f(1) Even
f(-1)=-f(1) Odd
ex f(x)=X^2 is even

There should be x not 1 or -1.

4. Still don't understand that is at all...

5. Originally Posted by KarlosK
Still don't understand that is at all...

if $\color{blue}f(-x)=f(x)$ then $\color{blue}f$ is an even function.
if $\color{blue}f(-x)=-f(x)$ then $\color{blue}f$ is an odd function.

6. In other words, use the definition of "even" and "odd" function.

$f(x)= e^{x^2}$ so $f(-x)= e^{(-x)^2}$ but $(-x)^2= x^2$ so $f(-x)= e^{x^2}= f(x)$.