help me..!! Sketch the graph of y=(2x-3)^2-5 for the domain 0<x<4.. please show me the step to get the answer..thanks!!
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Originally Posted by lindros help me..!! Sketch the graph of y=(2x-3)^2-5 for the domain 0<x<4.. please show me the step to get the answer..thanks!! Just enter different values for x into the equation. You have: $\displaystyle y = (2x-3)^2-5$ Set $\displaystyle x = 0$ then $\displaystyle y = (2*0 -3)^2-5$ set $\displaystyle x = 1$ then $\displaystyle y = (2*1-3)^2-5$ and so on until x = 4
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