I seem to be getting in a muddle on finding which function goes on top.
Can someone help
I understood it to be the one which has the largest y output when making the points of intersection the argument
BUT it seems to change on some functions
Thanks
No, if f(x)> g(x) on parts of the interval and g(x)> f(x) for other parts, then you will need to integrate (f(x)- g(x)) for the parts where f(x)> g(x), integrate (g(x)- f(x)) for the parts where g(x)> f(x), and add. The point is that "area" is positive and so you must always be integrating a positive function. If f(x)> g(x), then f(x)- g(x)> 0. If g(x)> f(x), then g(x)- f(x)> 0.