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Thread: equation of circle

  1. #1
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    equation of circle

    Find the equation of the circle with center at ((2)^,pi/4) and passing through the point (1,0)
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by cazimi View Post
    Find the equation of the circle with center at ((2)^,pi/4) and passing through the point (1,0)
    The point ((2)^,pi/4) in polars in Cartesian coordinates is (1, 1), which is
    the centre of your circle.

    The point (1, 0) in polars is (1, 0) in Cartesians, so as the circle passes
    through this point it has radius 1.

    So The circle is:

    (x-1)^2 + (y-1)^2 = 1

    RonL

    (Try to avoid mixing radians and degrees in the statement on a problem)
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