Find the equation of the circle with center at ((2)^½,pi/4) and passing through the point (1,0°)
The point ((2)^½,pi/4) in polars in Cartesian coordinates is (1, 1), which is
the centre of your circle.
The point (1, 0) in polars is (1, 0) in Cartesians, so as the circle passes
through this point it has radius 1.
So The circle is:
(x-1)^2 + (y-1)^2 = 1
RonL
(Try to avoid mixing radians and degrees in the statement on a problem)