Find the equation of the circle with center at ((2)^½,pi/4) and passing through the point (1,0°)

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- Mar 15th 2007, 10:20 PMcazimiequation of circle
Find the equation of the circle with center at ((2)^½,pi/4) and passing through the point (1,0°)

- Mar 16th 2007, 04:05 AMCaptainBlack
The point ((2)^½,pi/4) in polars in Cartesian coordinates is (1, 1), which is

the centre of your circle.

The point (1, 0) in polars is (1, 0) in Cartesians, so as the circle passes

through this point it has radius 1.

So The circle is:

(x-1)^2 + (y-1)^2 = 1

RonL

(Try to avoid mixing radians and degrees in the statement on a problem)