if someone could help i have an answer for the first one does it look okey. but am unsure how to tackle the 2nd one. many thanks (a) Log (x) + Log (y) = 2 y - x = 15 answer? (x=10/y) (y = 10/ x) (b) e^x+y = e^2x+4 x-y = 4
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Originally Posted by decoy808 if someone could help i have an answer for the first one does it look okey. but am unsure how to tackle the 2nd one. many thanks (a) Log (x) + Log (y) = 2 y - x = 15 answer? (x=10/y) (y = 10/ x) (b) e^x+y = e^2x+4 x-y = 4 a) Simultaneous equations should not be solved in terms of each other Solve the quadratic for y and then put any valid solutions back into the first equation to check for x Spoiler: y = -5 is not in the domain so discard it. Therefore .
Hello, decoy808! If I read it correctly, the second one has no solution . . . Equation [1] gives us: . With [2], we have an inconsistent system of equations: .
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