if someone could help i have an answer for the first one does it look okey. but am unsure how to tackle the 2nd one. many thanks(Nod)

(a)

Log (x) + Log (y) = 2

y - x = 15

answer?

(x=10/y)

(y = 10/ x)

(b)

e^x+y = e^2x+4

x-y = 4

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- Jan 30th 2010, 03:00 AMdecoy808solve simultaneously
if someone could help i have an answer for the first one does it look okey. but am unsure how to tackle the 2nd one. many thanks(Nod)

(a)

Log (x) + Log (y) = 2

y - x = 15

answer?

(x=10/y)

(y = 10/ x)

(b)

e^x+y = e^2x+4

x-y = 4 - Jan 30th 2010, 03:15 AMe^(i*pi)
- Jan 30th 2010, 05:27 AMSoroban
Hello, decoy808!

If I read it correctly, the second one has no solution . . .

Quote:

Equation [1] gives us: .

With [2], we have ansystem of equations: .*inconsistent*