Use the given information to solve the triangle:
C = 85 degrees 20', a = 35. c = 50
I am confused as to how to find A, B, and b of the triangle.
Any help is appreciated.
Hi iluvmathbutitshard,
Try using the law of cosines.
$\displaystyle c^2=a^2+b^2-2ab \cos C$
$\displaystyle 50^2=35^2+b^2-2(35)b \cos 85\frac{1}{3}$
You can solve for b here, then use that answer to solve for angle B by using the law of sines.
$\displaystyle \frac{\sin C}{c}=\frac{\sin B}{b}$
Or....
Use the law of sines to start with to find angle A.
$\displaystyle \frac{\sin 85\frac{1}{3}}{50}=\frac{\sin A}{35}$
Then, you'll have angle A and angle C. Easy to find angle B.
Use law of sines again to find b.
$\displaystyle \frac{\sin B}{b}=\frac{\sin C}{c}$