# ln is equal to

• January 27th 2010, 08:06 PM
jsl
ln is equal to
• January 27th 2010, 08:12 PM
pickslides
Here's a kicker...

$A\ln r+B\ln s$

$\ln r^{A}+\ln s^B$

$\ln (r^{A}\times s^B)$
• January 27th 2010, 08:19 PM
jsl
Thank you. That's what I thought, but I keep getting the wrong answer. I'll work on it some more.
• January 27th 2010, 09:28 PM
pickslides