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Math Help - Finding the zeros of large terms

  1. #1
    Junior Member
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    Finding the zeros of large terms

    I was wondering if there are easier ways or ways to break down large quadratics such as:

     <br />
3x^2 + 740x + 1000<br />

    I can't manipulate the window on my calculator to see the graph.


    ....
    You factor out the leading coefficient. But 740/3 and 1000/3 are still sketchy.
    Can I divide 1000, 740 and 3 by 10 and get somewhere with it?
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  2. #2
    Super Member bigwave's Avatar
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    Cool the graph

    assumming this =y

    if you want to see the graph

    http://www.wolframalpha.com/input/?i=3x^2+%2B+740x+%2B+1000%3Dy

    if this expression is =x
    quadratic formula:

    x = \frac{-740\pm\sqrt{740^2-(4)(3)(1000)}}{2(3)}<br />
\Rightarrow <br />
\frac{-740\pm20\sqrt{1339}}{6}

    these are very complicated answers hope the equation was copied correctly.
    Last edited by bigwave; January 27th 2010 at 10:02 PM. Reason: wording
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