seeing:

A(4,0) B(2,1)

find a unit vector in the direction of AB ( smal arrow above AB that begins from left to right) abd a vector of magnitude 3 in the opposite direction

thank you

- Jan 27th 2010, 07:37 PMalessandromangionefind a unit vector and a vector of magnitude 3 in the opposide direction
seeing:

A(4,0) B(2,1)

find a unit vector in the direction of AB ( smal arrow above AB that begins from left to right) abd a vector of magnitude 3 in the opposite direction

thank you - Jan 27th 2010, 08:09 PMfishcake
A unit vector is simply a vector with a magnitude of 1. To get the unit vector in the direction of the vector $\displaystyle \overrightarrow{A B}$, all you have to do is divide the components of the vector by its magnitude. This process is called normalization.

$\displaystyle \vec{AB}$

$\displaystyle = (2 - 4, 1 - 0)$

$\displaystyle = (-2, 1)$

Magnitude of $\displaystyle \vec{AB}$

$\displaystyle = \sqrt {{x}^{2}+{y}^{2}}$

$\displaystyle = \sqrt {{(-2)}^{2}+{1}^{2}}$

$\displaystyle = \sqrt {5}$

Unit vector in the direction of $\displaystyle \vec{AB}$

$\displaystyle = \left ( \frac{-2}{\sqrt{5}}, \frac{1}{\sqrt{5}} \right )$

To find the vector of magnitude 3 in the opposite direction of the vector $\displaystyle \vec{AB}$, you have to find the unit vector in the direction of $\displaystyle \vec{BA}$, which is in the opposite direction. Since the unit vector has a magnitude of 1, and you need a vector of magnitude 3, just multiply the unit vector by 3, and you'll get the answer. (Happy) - Jan 27th 2010, 08:23 PMalessandromangione
thank u very much!