solve for x,y, and z: x+y = 3z x^2 + y^2 = 5z x^3 + y^3 = 9z
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From Originally Posted by jmedsy x+y = 3z so (You might look to complete the sqaure here.) and
i still don't really see how its solved without some very lengthy, tedious algebra. what's the next step
Originally Posted by jmedsy without some very lengthy, tedious algebra. that's what I also see.
Hello, jmedsy! I think I've solved it . . . I'll get you started. Solve for Note that is a solution. In the following work, all the variables are nonzero. Square [1]: . . . . .[1] Cube [1]: . . . . .[2] Equate [1] and [2]: . Factor: . Your turn . . .
edited, thanks for the help
Last edited by jmedsy; Jan 27th 2010 at 08:20 PM.
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