solve for x,y, and z:

x+y = 3z

x^2 + y^2 = 5z

x^3 + y^3 = 9z

Printable View

- January 26th 2010, 05:25 PMjmedsysystem of 3 equations
solve for x,y, and z:

x+y = 3z

x^2 + y^2 = 5z

x^3 + y^3 = 9z - January 26th 2010, 05:30 PMpickslides
- January 26th 2010, 06:28 PMjmedsy
i still don't really see how its solved without some very lengthy, tedious algebra.

what's the next step - January 26th 2010, 06:42 PMpickslides
- January 26th 2010, 08:58 PMSoroban
Hello, jmedsy!

I think I've solved it . . . I'll get you started.

Quote:

Solve for

Note that is a solution.

In the following work, all the variables are nonzero.

Square [1]: .

. . . .[1]

Cube [1]: .

. . . .[2]

Equate [1] and [2]: .

Factor: .

Your turn . . .

- January 26th 2010, 10:25 PMjmedsy
edited, thanks for the help