solve for x,y
xy = e
x^(ln(y))=1/e^2
Hello, jmedsy!
A fascinating problem . . .
Solve for
. . .
. .
Take logs of equation [1]: .
Take logs of equation [2]: .
We have a system of equations: .
Substitute: .
From [3], we have: .
Substitute into [4]: .
Factor: .
. .
. .
We have: .
Back-substitute:
. .
. .
Two solutions: .