# Help Find Domain

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• Jan 25th 2010, 06:35 AM
BadMaterial
Help Find Domain
• Jan 25th 2010, 07:01 AM
HallsofIvy
Quote:

Originally Posted by BadMaterial

You cannot take the square root of a negative number and you cannot have 0 as a denominator. For what values of x are the expressions in side the square roots negative? For what values of x is the denominator in the second function 0? The domains of the first function is all numbers except those that make the expression inside the square root, 7x- 3, negative. The domain for the second function is all numbers except those that make the expression inside the square root, x, negative or that make the denominator, $6x^2- 5x+ 1$, equal to 0.
• Jan 25th 2010, 10:19 AM
OVechkin8
For the first one, anything under the sqare root has to be non-negative.

so 7-3x >/= 0

solve for x. and you should have you domain.
• Feb 21st 2010, 06:44 PM
salmansl
Domain
here's how you find the domain... 7-3x>0 so 7>3x divide both sides by three then you get 7/3>x interchange x<7/3 so the domain is all numbers less than 7/3

for the second one.. find the zeros and the domain is all real numbers except those zeros..