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Math Help - Equation of the line

  1. #1
    Junior Member Mist's Avatar
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    Equation of the line

    How do you solve this?

    The line  y= 4x+8 meets the y-axis at the point B. Find the equation of the line with gradient 2 that passes through the point B.

    Spoiler:
     y=4x+8
     4x+8=0
     4x=8
     x=2

    How'd you get the answer?
    totally confused
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  2. #2
    MHF Contributor
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    If x=0, then y=0+8=8.
    Therefore (0,8) is the y-axis crossing point.

    A line with gradient 2, passing through this point is y=2x+8

    since y=mx+c has gradient m.
    The gradient is called "m" as it is the multiplier of x
    when the linear equation is expressed in the form y=mx+c.
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  3. #3
    Super Member
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    Smile

    Quote Originally Posted by Mist View Post
    How do you solve this?

    The line  y= 4x+8 meets the y-axis at the point B. Find the equation of the line with gradient 2 that passes through the point B.

    Spoiler:
     y=4x+8
     4x+8=0
     4x=8
     x=2

    How'd you get the answer?
    totally confused
    hi
    write the equation of a line,
    y=mx+b,m is the gradient (slope),b is the y-intercept.
    m=2 and B=(0,8)
    y=2x+8.
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  4. #4
    Junior Member Mist's Avatar
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