How do you solve this?
The line meets the y-axis at the point B. Find the equation of the line with gradient 2 that passes through the point B.
If x=0, then y=0+8=8.
Therefore (0,8) is the y-axis crossing point.
A line with gradient 2, passing through this point is
since y=mx+c has gradient m.
The gradient is called "m" as it is the multiplier of x
when the linear equation is expressed in the form y=mx+c.