How do you solve this?

The line $\displaystyle y= 4x+8 $ meets the y-axis at the point B. Find the equation of the line with gradient 2 that passes through the point B.

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- Jan 25th 2010, 04:38 AMMistEquation of the line
How do you solve this?

The line $\displaystyle y= 4x+8 $ meets the y-axis at the point B. Find the equation of the line with gradient 2 that passes through the point B.

__Spoiler__: - Jan 25th 2010, 04:51 AMArchie Meade
If x=0, then y=0+8=8.

Therefore (0,8) is the y-axis crossing point.

A line with gradient 2, passing through this point is $\displaystyle y=2x+8$

since y=mx+c has gradient m.

The gradient is called "m" as it is the multiplier of x

when the linear equation is expressed in the form y=mx+c. - Jan 25th 2010, 04:56 AMRaoh
- Jan 25th 2010, 05:45 AMMist
Thanks