write the standard form of the equation
x^2-4x+8y+12=0
find the focus
i have it down to (x-2)^2=-8(y-8) is this right?
i'm not sure if you have to multiply the -8 on the right side of the equations by 4 since the focus is 1/4a
write the standard form of the equation
x^2-4x+8y+12=0
find the focus
i have it down to (x-2)^2=-8(y-8) is this right?
i'm not sure if you have to multiply the -8 on the right side of the equations by 4 since the focus is 1/4a