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Math Help - Solve the logarithm.

  1. #1
    Member
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    Jan 2010
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    Solve the logarithm.

    log5(x-1)+ log5(x-2)- log5(x+6)=0

    the base is 5.
    how do you do that on here? i can't seem to understand how to work the math tags button so I can put othedr notations like sigma or the integral sign...

    anyways, i got the answer to be x=4.82 or x=-0.83
    is that right?
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  2. #2
    Super Member

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    Lexington, MA (USA)
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    Hello, bhuang!

    Click on "Quote" to see my code . . .


    \log_5(x-1) + \log_5(x-2) - \log_5(x+6) \:=\:0

    i got the answer to be: x=4.82 or x=-0.83
    Is that right? . . . . almost

    That negative root is extraneous . . .
    Normally, we are not allowed logs of negative quantities.

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