$\displaystyle log5(x-1)$+$\displaystyle log5(x-2)$-$\displaystyle log5(x+6)$=0

the base is 5.

how do you do that on here? i can't seem to understand how to work the math tags button so I can put othedr notations like sigma or the integral sign...

anyways, i got the answer to be x=4.82 or x=-0.83

is that right?