2/x + 3/y = 4

3/x -2/y = 19

so I get x = 0.2 and y = -0.5

is x = 0 and y = 0 also a solution?

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- Jan 22nd 2010, 06:19 AMCarmineCortezsolutionn of two equations
2/x + 3/y = 4

3/x -2/y = 19

so I get x = 0.2 and y = -0.5

is x = 0 and y = 0 also a solution? - Jan 22nd 2010, 07:11 AMSoroban
Hello, CarmineCortez!

Quote:

. . $\displaystyle \begin{array}{ccc}\dfrac{2}{x} + \dfrac{3}{y} &=& 4 \\ \\ [-3mm] \dfrac{3}{x} -\dfrac{2}{y} &=& 19 \end{array}$

So I get: .$\displaystyle x = \frac{1}{5},\;y = -\frac{1}{2}$ . . . . Correct!

Is $\displaystyle x = 0,\:y = 0$ also a solution? . . . . no

In the original equations, you see that neither $\displaystyle x$ nor $\displaystyle y$ can be zero.