log2 (x+3) - log2 x = 2 I know that since this is a subtracting equation, I need to compress this to division. However after that I don't know what to do next. log2 (x+3) log2 x = 2 How I'm I able to solve for x?
Follow Math Help Forum on Facebook and Google+
Originally Posted by katchat64 log2 (x+3) - log2 x = 2 I know that since this is a subtracting equation, I need to compress this to division. However after that I don't know what to do next. log2 (x+3) log2 x = 2 How I'm I able to solve for x? actually, it is $\displaystyle \log_2 \left( \frac {x + 3}x \right) = 2$ (review your log rules!) Now, just do the anti-log, you get $\displaystyle \frac {x + 3}x = 2^2$ (since $\displaystyle \log_a b = c \Longleftrightarrow a^c = b$) now solve for $\displaystyle x$
View Tag Cloud