Does work? Why or why not?

Results 1 to 8 of 8

- Jan 21st 2010, 08:56 AM #1

- Joined
- Jan 2010
- Posts
- 43

- Jan 21st 2010, 09:09 AM #2

- Jan 21st 2010, 09:11 AM #3

- Joined
- Jan 2010
- Posts
- 43

- Jan 21st 2010, 09:43 AM #4

- Joined
- Aug 2009
- Posts
- 27

- Jan 21st 2010, 09:48 AM #5

- Joined
- Jan 2010
- Posts
- 43

Its a function f(g(x))=h correct? So you take the function of g, which in this case we found to be x^2+x-1 and plug that into the x values of f(x).

Doing so will give you 2(x^2+x-1)+8.

Factoring out will give you 2x^2+2x-2+8, add like terms and you will come to h, which is 2x^2+2x+6!

- Jan 21st 2010, 09:50 AM #6

- Jan 21st 2010, 09:53 AM #7

- Joined
- Aug 2009
- Posts
- 27

- Jan 21st 2010, 09:56 AM #8

- Joined
- Aug 2009
- Posts
- 27