Does work? Why or why not?

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- Jan 21st 2010, 09:56 AM #1

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- Jan 21st 2010, 10:09 AM #2

- Jan 21st 2010, 10:11 AM #3

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- Jan 21st 2010, 10:43 AM #4

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- Jan 21st 2010, 10:48 AM #5

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Its a function f(g(x))=h correct? So you take the function of g, which in this case we found to be x^2+x-1 and plug that into the x values of f(x).

Doing so will give you 2(x^2+x-1)+8.

Factoring out will give you 2x^2+2x-2+8, add like terms and you will come to h, which is 2x^2+2x+6!

- Jan 21st 2010, 10:50 AM #6

- Jan 21st 2010, 10:53 AM #7

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- Jan 21st 2010, 10:56 AM #8

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