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Math Help - log equation

  1. #1
    Super Member
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    log equation

    solve for x

     3^{x} e^{7x+2} = 15

     3^{x} e^{7x} e^{2} = 15

     3^{x} e^{7x} = \frac{15}{e^{2}}

     ln (3^{x} e^{7x}) = ln\frac{15}{e^{2}}

     ln 3^{x} + lne^{7x} = ln\frac{15}{e^{2}}

     x(ln3 +7) = ln \frac{15}{e^{2}}

     x = \frac{ln \frac{15}{e^{2}}}{ln3 +7}

    is this correct?
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  2. #2
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    Lexington, MA (USA)
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    Hello, Tweety!

    Correct! . . . Good job!

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