What is the domain of this relation? x² + 16y² = 16 Thanks.
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Originally Posted by shenton What is the domain of this relation? x² + 16y² = 16 Thanks. Divide by 16, x²/16 +y^2=1 Thus, x^2/4^2+y^2/1^2=1 This is an ellipse with vertical length of 4. Thus, the domain (the x part, which is vertical): -4<=x<=4
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