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Math Help - Geometric progression

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    Geometric progression

    Given the length of the first square is y cm and the ratio of the length of the sixth square to the first square is 1:32

    a)find the common ratio of the geometric progression

    b)if the sum of the area of the first three squares is 336/256 cm^2.Find the value of y.
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    Quote Originally Posted by mastermin346 View Post
    Given the length of the first square is y cm and the ratio of the length of the sixth square to the first square is 1:32

    a)find the common ratio of the geometric progression

    b)if the sum of the area of the first three squares is 336/256 cm^2.Find the value of y.
    a) Solve \frac{y r^5}{y} = \frac{1}{32} for r.

    b) Substitute everything you know (a = y, r = ...., n = 3, S = 336/256) into the formula for the sum of a geometric series and then solve for y.
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