Hello,

Could someone please help me by telling me what the best way to resolve the following equation into three partial fractions is?

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- Jan 16th 2010, 12:38 PMHNCMATHSPartial Fractions
Hello,

Could someone please help me by telling me what the best way to resolve the following equation into three partial fractions is?

- Jan 16th 2010, 12:44 PMe^(i*pi)
- Jan 16th 2010, 12:48 PMHNCMATHS
Sorry I do not understand your reply

- Jan 16th 2010, 01:46 PMArchie Meade

Now, you can ignore the denominators and multiply out the numerator on the right and compare terms with the left to find A, B and C.

The reason recommended now finding f(0), f(1) and f(-0.5) is because f(0) finds A since the parts with B and C will be zero.

You get and so on for B and C. - Jan 16th 2010, 01:47 PMDinkydoe
For more examples of partial fractions:

Partial fraction - Wikipedia, the free encyclopedia - Jan 16th 2010, 03:17 PMSoroban
Helolo, HNCMATHS!

I'll show you the method I was taught.

I think it's much simpler; don't know why everyone doesn't teach it.

Quote:

Resolve into partial fractions: .

Multiply by the LCD: .

Select some "good" values for

Let . . . . . . . . . . . . .

Let . . . . . . . . . . . .

Let . . .

Therefore: .

[Edit: oops! .I see that recommended this method.]

- Jan 16th 2010, 03:45 PMPlato
- Jan 17th 2010, 02:03 AMHNCMATHS
- Jan 17th 2010, 02:09 AMHNCMATHS
My main problem is that i dont understand how to work out that values that we need to plug in for

EDIT**

I think I have worked it out, has to equal 0 in the divisor? so in our case where we have ..... would equal

Its just clicked, again thank you all and i will be clicking thanks on all your posts. - Jan 17th 2010, 02:20 AMe^(i*pi)