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Math Help - finding range of function

  1. #1
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    finding range of function

    The function g is defined by  g(x) = x^{2} -8x +17 ,

     0\leq x

    Find the range of g.

    How do I find this? Is there a particular 'technique'?

    Thanks,
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  2. #2
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    Quote Originally Posted by Tweety View Post
    The function g is defined by  g(x) = x^{2} -8x +17 ,

     0\leq x

    Find the range of g.

    How do I find this? Is there a particular 'technique'?

    Thanks,
    hi
    since your function has no real roots,the parabola is strictly above the X-axis.
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  3. #3
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    Quote Originally Posted by Raoh View Post
    hi
    since your function has no real roots,the parabola is strictly above the X-axis.
    Thanks,

    So the range is all the values greater than or equal to zero?
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  4. #4
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    if you're able to find a global minimum for your function then i think you can find the range.
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  5. #5
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    Quote Originally Posted by Tweety View Post
    Thanks,

    So the range is all the values greater than or equal to zero?
    i think Strictly greater than zero.
    if we solve f'(x)=0.we'll find x=4 as a solution and at this point there is a global minimum.
    f(4)=1.
    therefore,the range is, [1,\infty )
    i might be wrong though...
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  6. #6
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    Quote Originally Posted by Tweety View Post
    The function g is defined by  g(x) = x^{2} -8x +17 ,

     0\leq x

    Find the range of g.

    How do I find this? Is there a particular 'technique'?

    Thanks,
    Draw the graph. Hint: Complete the square first.
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