1. ## Easy Question

Okay, my class has just started derivatives and I am stuck on a question.

For the following, find $\frac{dy}{dx}:$
$
y=\frac{10x^7 + 2x^2}{x^2}, x\neq 0
$

Any help will be appreciated. Please show complete working out.

2. Hi Mr Rayon

check this out

$
y=\frac{10x^7 + 2x^2}{x^2}=\frac{10x^7 }{x^2}+\frac{ 2x^2}{x^2}= 10x^5 + 2
$

so we can say

$
y=10x^5 + 2
$

Can you find $\frac{dy}{dx}$ from here?

3. Originally Posted by pickslides
Hi Mr Rayon

check this out

$
y=\frac{10x^7 + 2x^2}{x^2}=\frac{10x^7 }{x^2}+\frac{ 2x^2}{x^2}= 10x^5 + 2
$

so we can say

$
y=10x^5 + 2
$

Can you find $\frac{dy}{dx}$ from here?
dang i'm an idiot.
I thought the denominator was x^7. but if it had been x^7 i think i know what i should have done.

cheers