1. ## inverse function y=2(x^3)+3

Hello,

y=2x^3+3

the inverse should be

x=Cuberoot(y-3/2)

2. Originally Posted by l flipboi l
Hello,

y=2x^3+3

the inverse should be

x=Cuberoot(y-3/2)
well yes but no, you swap x and y and solve for y.

You mean to say

$y = \sqrt[3]{\frac{x-3}{2}}$

$y = \sqrt[3]{x-\frac{3}{2}}$

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