how will this graph look 2- log base3(x+1)
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Draw f(x)= log base3(x) move $\displaystyle \vec{u}=[-1,-2]$ Then you got g(x)= log base3(x + 1) -2 And h(x) = -g(x) (so transform it symmetrically agst x axis)
Hello math321 Originally Posted by math321 how will this graph look 2- log base3(x+1) See the attached diagram. Grandad
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