Determine all complex solutions of the equation z^4 - 4z^2 + 16 = 0 in Cartesian form.
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Originally Posted by mamt6 Determine all complex solutions of the equation z^4 - 4z^2 + 16 = 0 in Cartesian form. Note that this equation is quadratic in . Take to turn the equation into . Apply the quadratic formula to get . Note that in complex polar form we have and To get the four solutions for , evaluate and by applying DeMoivre's Theorem. Can you finish this off?
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