How can I show that -ln(4) = ln(0.25). A hint would be fine...
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Originally Posted by Henryt999 How can I show that -ln(4) = ln(0.25). A hint would be fine... Hint Spoiler: Lose the logarithms
Originally Posted by Henryt999 How can I show that -ln(4) = ln(0.25). A hint would be fine... Add a zero to your equation: $\displaystyle -\ln(4) = 0-\ln(4) = \ln(1)-\ln(4)$ I'll leave the rest for you.
It's a basic property of logarithms: $\displaystyle a\cdot \ln(b) = \ln(b^a)$ So if $\displaystyle a = -1, b= 4$? what is $\displaystyle b^{a}$
That was very very easy ops ops ops
Hello, Henryt999! How can I show that: .$\displaystyle -\ln(4) \:=\: \ln(0.25)$ The left side is: .$\displaystyle -1\cdot\ln(4) \;=\;\ln\left(4^{-1}\right) \;=\;\ln\left(\frac{1}{4}\right) \;=\;\ln(0.25)$
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