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Math Help - Show that -ln(4) = ln(0.25)???

  1. #1
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    Show that -ln(4) = ln(0.25)???

    How can I show that -ln(4) = ln(0.25).
    A hint would be fine...
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Henryt999 View Post
    How can I show that -ln(4) = ln(0.25).
    A hint would be fine...
    Hint

    Spoiler:
    Lose the logarithms
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  3. #3
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    Quote Originally Posted by Henryt999 View Post
    How can I show that -ln(4) = ln(0.25).
    A hint would be fine...
    Add a zero to your equation:

    -\ln(4) = 0-\ln(4) = \ln(1)-\ln(4)

    I'll leave the rest for you.
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  4. #4
    Senior Member Dinkydoe's Avatar
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    It's a basic property of logarithms: a\cdot \ln(b) = \ln(b^a)

    So if a = -1, b= 4? what is b^{a}
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  5. #5
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    ops

    That was very very easy ops ops ops
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  6. #6
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    Hello, Henryt999!

    How can I show that: .  -\ln(4) \:=\: \ln(0.25)

    The left side is: . -1\cdot\ln(4) \;=\;\ln\left(4^{-1}\right) \;=\;\ln\left(\frac{1}{4}\right) \;=\;\ln(0.25)


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