# Math Help - Show that -ln(4) = ln(0.25)???

1. ## Show that -ln(4) = ln(0.25)???

How can I show that -ln(4) = ln(0.25).
A hint would be fine...

2. Originally Posted by Henryt999
How can I show that -ln(4) = ln(0.25).
A hint would be fine...
Hint

Spoiler:
Lose the logarithms

3. Originally Posted by Henryt999
How can I show that -ln(4) = ln(0.25).
A hint would be fine...

$-\ln(4) = 0-\ln(4) = \ln(1)-\ln(4)$

I'll leave the rest for you.

4. It's a basic property of logarithms: $a\cdot \ln(b) = \ln(b^a)$

So if $a = -1, b= 4$? what is $b^{a}$

5. ## ops

That was very very easy ops ops ops

6. Hello, Henryt999!

How can I show that: . $-\ln(4) \:=\: \ln(0.25)$

The left side is: . $-1\cdot\ln(4) \;=\;\ln\left(4^{-1}\right) \;=\;\ln\left(\frac{1}{4}\right) \;=\;\ln(0.25)$