make x the subject

y=5(1-e^(-x))

first i expand it

so

y=5-5e^(-x)

loge(y)=loge(5)+loge(e5x)

loge(y)-loge(5)=5x

x=loge(y)-loge(5)/5 ??

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- Jan 8th 2010, 10:53 PMsmmmcMaking x the subject in an exponential equation
make x the subject

y=5(1-e^(-x))

first i expand it

so

y=5-5e^(-x)

loge(y)=loge(5)+loge(e5x)

loge(y)-loge(5)=5x

x=loge(y)-loge(5)/5 ?? - Jan 8th 2010, 10:58 PMProve It
- Jan 8th 2010, 11:07 PMsmmmc
the answer says loge(5/5-y) ?

- Jan 8th 2010, 11:11 PMSudharaka
Dear smmmc,

Of course, Therefore what Prove it had shown is the answer. - Jan 8th 2010, 11:12 PMmr fantastic
- Jan 9th 2010, 05:28 AMHallsofIvy