show that (k+1)x^2 -2x -k = 0 has a solution for all values of k. i used b^2-4ac=0 i ended up with k=-2, not sure what the step is next thanks
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Originally Posted by smmmc show that (k+1)x^2 -2x -k = 0 has a solution for all values of k. i used b^2-4ac=0 i ended up with k=-2, not sure what the step is next thanks All you have to do is show that for all values of k.
Hello, smmmc! Show that has a solution for all values of . i used . . Why zero? i ended up with k = -2 . . . . How? And it can be shown that is always positive.
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