show that (k+1)x^2 -2x -k = 0 has a solution for all values of k.

i used b^2-4ac=0

i ended up with k=-2, not sure what the step is next

thanks

Printable View

- January 8th 2010, 05:47 PMsmmmcsolutions for k values
show that (k+1)x^2 -2x -k = 0 has a solution for all values of k.

i used b^2-4ac=0

i ended up with k=-2, not sure what the step is next

thanks - January 8th 2010, 05:53 PMmr fantastic
- January 8th 2010, 07:36 PMSoroban
Hello, smmmc!

Quote:

Show that has a solution for all values of .

i used . . Why zero?

i ended up with k = -2 . . . . How?

And it can be shown that is always positive.