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Math Help - Solving for x in this natural log inequality

  1. #1
    Junior Member BugzLooney's Avatar
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    Solving for x in this natural log inequality

    e^2-3x > 5; solve for x

    So I went forward and figured that ln(5) < 2-3x

    I don't know where to go from there, I thought I had a couple of answers but they weren't right. I had the other parts of similar questions right but this ones stumping me. Any help?
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  2. #2
    MHF Contributor
    skeeter's Avatar
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    Quote Originally Posted by BugzLooney View Post
    e^2-3x > 5; solve for x

    So I went forward and figured that ln(5) < 2-3x

    I don't know where to go from there, I thought I had a couple of answers but they weren't right. I had the other parts of similar questions right but this ones stumping me. Any help?
    e^{2-3x} > 5

    2-3x > \ln{5}

    -3x > \ln{5} - 2

    3x < 2 - \ln{5}

    x < \frac{2-\ln{5}}{3}
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  3. #3
    Junior Member BugzLooney's Avatar
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    Hey thanks that is easy I think I got something close but thanks for clearing that up! Maybe when I brush up my skills I'll be helping some guys around here.
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