The first time you draw, there are 10 balls, 8 of which are NOT 2 or 3. The probability you will not draw 2 or 3 is 8/10. Assuming you did not draw a 2 or 3, there are now 9 balls left 7 of which are not 2 or 3. The probabilty you do not draw 2 or 3 is now 7/9. Then there are 8 balls, 6 of which are not 2 or 3- probability of drawing 2 or 3 is 6/8... It should become clear that the probability of not drawing a 2 or 3 in 6 draws is

.

2. What is the probability that I will draw a number 2 AND a number 3 ball?