Please, just use "regular" print! Because most internet readers do not respect "spaces", I cannot read your functions.
The question is: Find the points to y = 2/(3x-2) where the tangent is parallel to the line y = (-3/2)x - 1.
I have gotten this far: (-3/2) = -6/(3x-2)^2
Where do I go from there?
P.S. Thank you for what was a seemingly easy solution. I cannot believe I did not see that....D'oh!