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Math Help - Simple equation problem

  1. #1
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    Simple equation problem

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  2. #2
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     y^2 cannot be a negative number.
    therefore the answer is  \oslash
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  3. #3
    Junior Member shinhidora's Avatar
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    Quote Originally Posted by .::MadMaX::. View Post
    y^2 = -\frac{1}{4}
    y = \sqrt{-\frac{1}{4}}
    y = ERROR

    and thus as vonflex1 said: y^2 can't be negative
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  4. #4
    Super Member bigwave's Avatar
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    there is an imaginary answer

     <br />
y = \frac{\sqrt{-1}}{\sqrt{4}} = \frac{i}{2}<br />
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  5. #5
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    Ok,this simple equation is part of bigger complex numbers task:



    and general solution for this task is:



    than solution for must be in order to match general solution of this task?
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  6. #6
    Super Member bigwave's Avatar
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    not sure how that works?
    \left(-\frac{1}{2}\right)^2  \ne -\frac{1}{4}

    but

    \left(-\frac{i}{2}\right)^2  = -\frac{1}{4}
    Last edited by bigwave; January 5th 2010 at 11:05 AM. Reason: curious
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  7. #7
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    Try to solve entire problem,than you will get to the part where

    and I just don't know how solution of the task is ???

    Ok,I agree about x value,but how did they get that y value? ???
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  8. #8
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    Quote Originally Posted by .::MadMaX::. View Post
    Try to solve entire problem,than you will get to the part where

    and I just don't know how solution of the task is ???

    Ok,I agree about x value,but how did they get that y value? ???
    Your original relation can be written as |z| = |z + 1| and this defines a line (the perpendicular bisector of the line segment joining z = 0 and z = -1). If you substitute z = x + iy the same answer is easily got.

    I have no idea where all your other stuff has come from since you refuse to show any of your working.
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  9. #9
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    |Z|=-\frac{1}{2}+ki

    |Z+1|=\frac{1}{2}+ki

    |Z|=\sqrt{(-0.5)^2+k^2}=\sqrt{\frac{1}{4}+k^2}

    |Z+1|=\sqrt{(0.5)^2+k^2}=\sqrt{\frac{1}{4}+k^2}
    Attached Thumbnails Attached Thumbnails Simple equation problem-z-.jpg  
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