Results 1 to 3 of 3

Math Help - Complex numbers problem!

  1. #1
    Newbie
    Joined
    Jan 2010
    Posts
    14

    Complex numbers problem!

    How to find complex numbers in form z=x+yi which satisfies :




    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Aug 2009
    From
    Israel
    Posts
    976
    Let z=x+iy be a solution of this equation, then:

    (x+iy)(x-iy) -2i = 2i(x-iy) \Rightarrow (x-iy)(x+iy-2i)=2i

    Now,

    (x-iy)(x+i(y-2)) = x^2-2xi+y^2-2

    Substitute back and get: x^2+y^2-2-2xi = 2i \rightarrow -2x = 2 \Rightarrow x=-1

    x^2+y^2=2\Rightarrow y^2=1 \Rightarrow y=\pm 1

    So our solutions are:
    z_1=-1+i
    z_2=\bar{z_1} = -1-i
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jan 2010
    Posts
    14
    Thank you,it helped me alot! Cheers!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Complex Numbers Problem
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 16th 2011, 11:42 PM
  2. Problem with Complex numbers.
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: October 17th 2008, 08:44 AM
  3. Complex numbers problem need help
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: July 28th 2008, 11:21 AM
  4. Complex Numbers Problem
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: January 17th 2008, 09:07 AM
  5. Replies: 1
    Last Post: May 24th 2007, 04:49 AM

Search Tags


/mathhelpforum @mathhelpforum