Originally Posted by

**purpledinosaur** Consider the equation 10 = 2^x

(a) Solve the equation for x by taking the common logarithm of both sides.

Answer :

log10 = xlog2

x = log10/log2

(b) use the result to show that 10 = 2^1/log2

I understand that this works because log10 = 1, thus 1/log2 is the same thing as log10/log2. However, how does the power law of logarithm apply here? If i were to prove this question algebraically.

Simply substitute x = log10/log2 = 1/log2 into your original equation 10 = 2^x

(c) apply algebraic reasoning to show that10 = 3^1/log10

It doesn't.